## locus of P such A(16) & B (3,5). Find equartion of locus of P such that angleAPB is that right angled.

Question

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## Answers ( )

Answer:16×3=48

16×5=80

48-80=48

then the p is 48

Answer:x² + y² – 4x – 11y + 28 = 0

Step-by-step explanation:P = x,y

A = 1,6

B = 3,5

APB = 90°

which implies it is a right angled triangle having a right angle at P

PA² + PB² = AB²

(x – 1)² + (y – 6)² + (x – 3)² + (y – 5)² = (1-3)² + (6-5)²

after solving you will get,

2x² + 2y² – 8x – 22y + 61 = 5

2x² + 2y² – 8x – 22y + 56 = 0

divide 2 on both sides

x² + y² – 4x – 11y + 28 = 0